0=16t^2+832t+50

Solution for 0=16t^2+832t+50 equation:

0=16t^2+832t+50

We move all terms to the left:

0-(16t^2+832t+50)=0

We add all the numbers together, and all the variables

-(16t^2+832t+50)=0

We get rid of parentheses

-16t^2-832t-50=0

a = -16; b = -832; c = -50;
Δ = b2-4ac
Δ = -8322-4·(-16)·(-50)
Δ = 689024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{689024}=\sqrt{64*10766}=\sqrt{64}*\sqrt{10766}=8\sqrt{10766}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-832)-8\sqrt{10766}}{2*-16}=\frac{832-8\sqrt{10766}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-832)+8\sqrt{10766}}{2*-16}=\frac{832+8\sqrt{10766}}{-32}
$